Large sparse array data structure
This problem was asked by Facebook.
You have a large array with most of the elements as zero.
Use a more space-efficient data structure, SparseArray, that implements the same interface:
init(arr, size)
: initialize with the original large array and size.set(i, val)
: updates index at i with val.get(i)
: gets the value at index i.
My Solution(C++):
#include <iostream>
#include <map>
class SparseArray{
// sparse array data structure based on map
public:
SparseArray(int);
void set(int, int);
int get(int);
std::map<int, int> H;
int size;
};
SparseArray::SparseArray(int size){
// constructor
this->size = size;
}
void SparseArray::set(int i, int val){
// set method
if (i>=this->size || i<0 ){
std::cout << "Invalid Index" << std::endl;
return;
}
this->H[i] = val;
return;
}
int SparseArray::get(int i){
// get method
if (i<0 || i>=this->size){
std::cout << "Invalid Index" << std::endl;
return -1;
}
if (this->H.find(i) == this->H.end()){
return 0;
}
return this->H[i];
}
void test(){
// builds and runs test cases
SparseArray sa(100);
sa.set(1, 4);
std::cout << sa.get(6) << std::endl;
std::cout << sa.get(1) << std::endl;
std::cout << sa.get(101) << std::endl;
}
int main(){
// run the test
test();
return 0;
}