Max Number of K-Sum Pairs - Two Sum Approach
Problem Statement:
You are given an integer array nums
and an integer k
.
In one operation, you can pick two numbers from the array whose sum equals k
and remove them from the array.
Return the maximum number of operations you can perform on the array.
Example 1:
Input: nums = [1,2,3,4], k = 5 Output: 2 Explanation: Starting with nums = [1,2,3,4]: - Remove numbers 1 and 4, then nums = [2,3] - Remove numbers 2 and 3, then nums = [] There are no more pairs that sum up to 5, hence a total of 2 operations.
Example 2:
Input: nums = [3,1,3,4,3], k = 6 Output: 1 Explanation: Starting with nums = [3,1,3,4,3]: - Remove the first two 3's, then nums = [1,4,3] There are no more pairs that sum up to 6, hence a total of 1 operation.
Constraints:
1 <= nums.length <= 105
1 <= nums[i] <= 109
1 <= k <= 109
Solution:
We use a HashMap based standard two sum approach.
class Solution {
public:
int maxOperations(vector<int>& nums, int target) {
unordered_map<int,int> comps;
int ctr=0;
for (int n: nums)
{
if (comps.count(n) && comps[n]>0)
{
ctr++;
comps[n]--;
} else comps[target-n]++;
}
return ctr;
}
};
TC: O(n)
SC: O(n)