Encode and Decode TinyURL - Easy HashMap solution
Problem Statement:
Note: This is a companion problem to the System Design problem: Design TinyURL.
TinyURL is a URL shortening service where you enter a URL such as https://leetcode.com/problems/design-tinyurl
and it returns a short URL such as http://tinyurl.com/4e9iAk
. Design a class to encode a URL and decode a tiny URL.
There is no restriction on how your encode/decode algorithm should work. You just need to ensure that a URL can be encoded to a tiny URL and the tiny URL can be decoded to the original URL.
Implement the Solution
class:
Solution()
Initializes the object of the system.String encode(String longUrl)
Returns a tiny URL for the givenlongUrl
.String decode(String shortUrl)
Returns the original long URL for the givenshortUrl
. It is guaranteed that the givenshortUrl
was encoded by the same object.
Example 1:
Input: url = "https://leetcode.com/problems/design-tinyurl" Output: "https://leetcode.com/problems/design-tinyurl" Explanation: Solution obj = new Solution(); string tiny = obj.encode(url); // returns the encoded tiny url. string ans = obj.decode(tiny); // returns the original url after deconding it.
Constraints:
1 <= url.length <= 104
url
is guranteed to be a valid URL.
Solution:
class Solution {
public:
unordered_map<int,string> int2url;
unordered_map<string,int> url2int;
string base_url = "http://tiny.io/";
// Encodes a URL to a shortened URL.
string encode(string longUrl) {
if (url2int.find(longUrl)==url2int.end())
{
int ctr=url2int.size();
url2int[longUrl] = ctr;
int2url[ctr] = longUrl;
}
return base_url+to_string(url2int[longUrl]);
}
// Decodes a shortened URL to its original URL.
string decode(string shortUrl) {
string nstr = string(shortUrl.begin()+15,shortUrl.end());
int n = stoi(nstr);
return int2url[n];
}
};